n^2+2n=4n-5

Solution for n^2+2n=4n-5 equation:

Simplifying
n2 + 2n = 4n + -5

Reorder the terms:
2n + n2 = 4n + -5

Reorder the terms:
2n + n2 = -5 + 4n

Solving
2n + n2 = -5 + 4n

Solving for variable 'n'.

Reorder the terms:
5 + 2n + -4n + n2 = -5 + 4n + 5 + -4n

Combine like terms: 2n + -4n = -2n
5 + -2n + n2 = -5 + 4n + 5 + -4n

Reorder the terms:
5 + -2n + n2 = -5 + 5 + 4n + -4n

Combine like terms: -5 + 5 = 0
5 + -2n + n2 = 0 + 4n + -4n
5 + -2n + n2 = 4n + -4n

Combine like terms: 4n + -4n = 0
5 + -2n + n2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + -2n + -5 + n2 = 0 + -5

Reorder the terms:
5 + -5 + -2n + n2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -2n + n2 = 0 + -5
-2n + n2 = 0 + -5

Combine like terms: 0 + -5 = -5
-2n + n2 = -5

The n term is -2n.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2n + 1 + n2 = -5 + 1

Reorder the terms:
1 + -2n + n2 = -5 + 1

Combine like terms: -5 + 1 = -4
1 + -2n + n2 = -4

Factor a perfect square on the left side:
(n + -1)(n + -1) = -4

Can't calculate square root of the right side.

The solution to this equation could not be determined.